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std::set_symmetric_difference

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Algorithm Bibliothek
Funktionen
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Functions
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Nicht-modifizierende Sequenz Operationen
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Non-modifying sequence operations
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Modifizierende Sequenz Operationen
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Modifying sequence operations
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Partitionierungsoperationen
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Partitioning operations
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Sortierung Operationen (auf sortierten Bereiche)
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Sorting operations (on sorted ranges)
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Binary Suchaktionen (auf sortierten Bereiche)
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Binary search operations (on sorted ranges)
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Set-Operationen (auf sortierten Bereiche)
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Set operations (on sorted ranges)
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set_difference
set_intersection
set_symmetric_difference
set_union
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Heap operations
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Minimum/maximum operations
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Numeric operations
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C-Bibliothek
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C library
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Defined in header <algorithm>
template< class InputIt1, class InputIt2, class OutputIt >

OutputIt set_symmetric_difference( InputIt1 first1, InputIt1 last1,
                                   InputIt2 first2, InputIt2 last2,

                                   OutputIt d_first );
(1)
template< class InputIt1, class InputIt2,

          class OutputIt, class Compare >
OutputIt set_symmetric_difference( InputIt1 first1, InputIt1 last1,
                                   InputIt2 first2, InputIt2 last2,

                                   OutputIt d_first, Compare comp );
(2)
Kopiert die Elemente aus der sortierten Reihe [first1, last1) die nicht in der sortierten Reihe [first2, last2) und die Elemente aus der sortierten Reihe [first2, last2) die nicht in der sortierten Reihe [first1, last1) dem Bereich beginnend bei d_first gefunden wurden gefunden. Das resultierende Spektrum wird auch sortiert. Die erste Version rechnet sowohl Eingangsbereiche mit operator< sortiert werden, rechnet die zweite Version sie mit dem angegebenen Vergleichsfunktion comp sortiert werden. Wenn ein Element ist m mal gefunden [first1, last1) und n Mal in [first2, last2), wird es an d_first genau std::abs(m-n) Mal kopiert werden. Wenn m>n, dann die letzte m-n dieser Elemente aus [first1,last1) kopiert werden, sonst werden die letzten n-m Elemente aus [first2,last2) kopiert. Die daraus resultierende Bereich kann nicht mit einem der Eingangsbereiche überschneiden .
Original:
Copies the elements from the sorted range [first1, last1) which are not found in the sorted range [first2, last2) and the elements from the sorted range [first2, last2) which are not found in the sorted range [first1, last1) to the range beginning at d_first. The resulting range is also sorted. The first version expects both input ranges to be sorted with operator<, the second version expects them to be sorted with the given comparison function comp. If some element is found m times in [first1, last1) and n times in [first2, last2), it will be copied to d_first exactly std::abs(m-n) times. If m>n, then the last m-n of those elements are copied from [first1,last1), otherwise the last n-m elements are copied from [first2,last2). The resulting range cannot overlap with either of the input ranges.
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Inhaltsverzeichnis

[Bearbeiten] Parameter

first1, last1 -
die erste Reihe von Elementen sortiert
Original:
the first sorted range of elements
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first2, last2 -
die zweite sortierten Bereich von Elementen
Original:
the second sorted range of elements
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comp - comparison function which returns ​true if the first argument is less than the second.

The signature of the comparison function should be equivalent to the following:

 bool cmp(const Type1 &a, const Type2 &b);

The signature does not need to have const &, but the function must not modify the objects passed to it.
The types Type1 and Type2 must be such that objects of types InputIt1 and InputIt2 can be dereferenced and then implicitly converted to Type1 and Type2 respectively. ​

Type requirements
-
InputIt1 must meet the requirements of InputIterator.
-
InputIt2 must meet the requirements of InputIterator.
-
OutputIt must meet the requirements of OutputIterator.

[Bearbeiten] Rückgabewert

Iterator über das Ende der konstruiert Bereich .
Original:
Iterator past the end of the constructed range.
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[Bearbeiten] Komplexität

Allenfalls 2·(N1+N2-1) Vergleiche, wo N1 = std::distance(first1, last1) und N2 = std::distance(first2, last2) .
Original:
At most 2·(N1+N2-1) comparisons, where N1 = std::distance(first1, last1) and N2 = std::distance(first2, last2).
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[Bearbeiten] Mögliche Implementierung

First version
template<class InputIt1, class InputIt2, class OutputIt>
OutputIt set_difference(InputIt1 first1, InputIt1 last1,
                        InputIt2 first2, InputIt2 last2,
                        OutputIt d_first)
{
    while (first1 != last1) {
        if (first2 == last2) return std::copy(first1, last1, d_first);
 
        if (*first1 < *first2) {
            *d_first++ = *first1++;
        } else {
            if (*first2 < *first1) {
                *d_first++ = *first2;
            } else {
                ++first1;
            }
            ++first2;
        }
    }
    return std::copy(first2, last2, d_first);
}
Second version
template<class InputIt1, class InputIt2,
         class OutputIt, class Compare>
OutputIt set_difference(InputIt1 first1, InputIt1 last1,
                        InputIt2 first2, InputIt2 last2,
                        OutputIt d_first, Compare comp)
{
    while (first1 != last1) {
        if (first2 == last2) return std::copy(first1, last1, d_first);
 
        if (comp(*first1, *first2)) {
            *d_first++ = *first1++;
        } else {
            if (comp(*first2, *first1)) {
                *d_first++ = *first2;
            } else {
                ++first1;
            }
            ++first2;
        }
    }
    return std::copy(first2, last2, d_first);
}

[Bearbeiten] Beispiel

#include <iostream>
#include <vector>
#include <algorithm>
#include <iterator>
int main()
{
    std::vector<int> v1{1,2,3,4,5,6,7,8     };
    std::vector<int> v2{        5,  7,  9,10};
    std::sort(v1.begin(), v1.end());
    std::sort(v2.begin(), v2.end());
 
    std::vector<int> v_intersection;
 
    std::set_symmetric_difference(
        v1.begin(), v1.end(),
        v2.begin(), v2.end(),
        std::back_inserter(v_intersection));
 
    for(int n : v_intersection)
        std::cout << n << ' ';
}

Output:

1 2 3 4 6 8 9 10

[Bearbeiten] Siehe auch

liefert true, wenn ein Satz ist eine Teilmenge des anderen
Original:
returns true if one set is a subset of another
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(Funktions-Template) [edit]
berechnet die Differenz zwischen zwei Sätzen
Original:
computes the difference between two sets
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(Funktions-Template) [edit]
computes the union of two sets
(Funktions-Template) [edit]
berechnet den Schnittpunkt von zwei Sätzen
Original:
computes the intersection of two sets
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(Funktions-Template) [edit]